![Porsche 911 Turbo MOD. It feels like Speed Champions are always too long so this lost 1 stud from the middle. : r/lego Porsche 911 Turbo MOD. It feels like Speed Champions are always too long so this lost 1 stud from the middle. : r/lego](https://preview.redd.it/xe9wx4vhmof31.jpg?auto=webp&s=0c1bbbeaaf7e25da00fd013c6669dff2afd719b3)
Porsche 911 Turbo MOD. It feels like Speed Champions are always too long so this lost 1 stud from the middle. : r/lego
![Porsche 911 RSR and 911 Turbo 3.0 75888 | Speed Champions | Buy online at the Official LEGO® Shop US Porsche 911 RSR and 911 Turbo 3.0 75888 | Speed Champions | Buy online at the Official LEGO® Shop US](https://photorankmedia-a.akamaihd.net/media/u/r/h/urh8vm4/normal.jpg)
Porsche 911 RSR and 911 Turbo 3.0 75888 | Speed Champions | Buy online at the Official LEGO® Shop US
![LEGO MOC Speed champions style Porsche 911 3.2 Carrera 8 Studs wide by frozenkuku | Rebrickable - Build with LEGO LEGO MOC Speed champions style Porsche 911 3.2 Carrera 8 Studs wide by frozenkuku | Rebrickable - Build with LEGO](https://cdn.rebrickable.com/media/thumbs/mocs/moc-39047.jpg/1000x800.jpg)
LEGO MOC Speed champions style Porsche 911 3.2 Carrera 8 Studs wide by frozenkuku | Rebrickable - Build with LEGO
![LEGO Speed Champions 75888: Porsche 911 RSR and 911 Turbo [Review] - The Brothers Brick | The Brothers Brick LEGO Speed Champions 75888: Porsche 911 RSR and 911 Turbo [Review] - The Brothers Brick | The Brothers Brick](https://s3-us-west-2.amazonaws.com/media.brothers-brick.com/wp-content/uploads/2018/10/75888-Porsche-911-RSR-and-911-Turbo-8-640x336.jpg)
LEGO Speed Champions 75888: Porsche 911 RSR and 911 Turbo [Review] - The Brothers Brick | The Brothers Brick
![Porsche 911 RSR and 911 Turbo 3.0 75888 | Speed Champions | Buy online at the Official LEGO® Shop US Porsche 911 RSR and 911 Turbo 3.0 75888 | Speed Champions | Buy online at the Official LEGO® Shop US](https://www.lego.com/cdn/cs/set/assets/bltefd68523fa83d10e/75888.jpg?fit=bounds&format=jpg&quality=80&width=528&height=528&dpr=1)